Advanced Physics Forums
User Name
Password
Home FAQ Members List Calendar News Search Today's Posts Mark Forums Read



Go Back   Advanced Physics Forums > Lecture and Theory Topics > Classical Mechanics

Reply
 
Thread Tools Display Modes
Old 2005 October 25th, 23:24   #1
ee7klt
Quark
 
Join Date: 2005 Oct
Posts: 3
ee7klt is an unknown quantity
spherical pendulum using N2

Hi All,

I'm trying to solve the spherical pendulum using newton's laws, but am coming up with something different than that obtained using the lagrangian formalism. The two forces acting on the point mass are the tension $T$ and the gravitational force $mg$, which (in the case where it's moving in a circle of constant \theta) should conspire to produce the centripetal force necessary to keep it in circular motion. Thus,

r: $T - m g \cos \theta = m \ddot{r}$
\theta: $m g \sin \theta = m (r \ddot{\theta} + \dot{r} \dot{\theta}$
\phi : $r \sin \theta \ddot{\phi} + r \cos \theta \dot{theta} \dot{\phi} + \dot{r} sin \theta \dot{\phi} = 0$

In particular, this yields $T = mg \cos \theta$ with the constraint $r = l$ for the dynamic equilibrium case \theta = const. but I know the answer to be $T = -m l \sin^2 \theta {\dot{phi}}^2 - m g \cos \theta$.

Any ideas ?
ee7klt is offline   Reply With Quote
Old 2005 October 26th, 00:46   #2
Xerxes314
Administrator


 
Xerxes314's Avatar
 
Join Date: 2003 Aug
Location: Jefferson Lab
Posts: 2,174
Xerxes314 has disabled reputation
Send a message via ICQ to Xerxes314 Send a message via AIM to Xerxes314 Send a message via MSN to Xerxes314 Send a message via Yahoo to Xerxes314
You just need to add the centripetal force mv2/r, and then convert v to phi.

Xerxes
Xerxes314 is offline   Reply With Quote
Old 2005 October 26th, 13:33   #3
jbelew
Asteroid
 
Join Date: 2004 Apr
Posts: 166
jbelew has posted things of interest
dynamic equilibrium, ouch!
jbelew is offline   Reply With Quote
Reply


Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)
 
Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is On

Forum Jump


All times are GMT -4. The time now is 11:37.

Powered by vBulletin® Version 3.8.1
Copyright ©2000 - 2010, Jelsoft Enterprises Ltd.
Style developed by: vBulletinStyles
Copyright Advanced Physics Forums


physics books